To calculate the wavelength ($\lambda$) of electromagnetic radiation, we can use the formula:

$\lambda = \frac{c}{f}$

Where:

• $c$ is the speed of light in a vacuum ($3.00 \times 10^8 \, \text{m/s}$)
• $f$ is the frequency of the radiation ($1.22 \times 10^8 \, \text{s}^{-1}$)

Substituting the given values:

$\lambda = \frac{3.00 \times 10^8 \, \text{m/s}}{1.22 \times 10^8 \, \text{s}^{-1}}$

Now, let's compute this.

$\lambda \approx 2.46 \, \text{m}$

So, the wavelength of the electromagnetic radiation is approximately 2.46 meters.

Would you like more details or further clarification?

Here are 5 related questions:

1. What is the relationship between wavelength and frequency in the electromagnetic spectrum?
2. How does the wavelength change when frequency increases?
3. What types of electromagnetic radiation correspond to wavelengths around 2.46 meters?
4. How is the speed of light related to electromagnetic waves?
5. What are the typical applications of electromagnetic waves with a frequency of $1.22 \times 10^8 \, \text{s}^{-1}$?

Tip: The wavelength and frequency of a wave are inversely proportional: as frequency increases, wavelength decreases.